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erad1cateMay 20 2009, 22:57:39 UTC 6 years ago

korean_guy_01May 20 2009, 23:06:44 UTC 6 years ago

erad1cateMay 20 2009, 23:17:52 UTC 6 years ago

BUT:

Pick any positive value close to 0, you can find an x for e^x to give that value.

Example, for instance .001 = e^(-6.907755...)

If you're posting in algorithms, I'm assuming a value close to 0 at some point is 0 if you're looking for a numerical solution.

itmanMay 21 2009, 00:21:33 UTC 6 years ago

eps -> 0, log(eps) -> -infty

roadriverrailMay 20 2009, 22:59:48 UTC 6 years ago

joee_girlMay 20 2009, 23:14:21 UTC 6 years ago

2. e^k (for k>0) increases as k increases. This should be easy to see from the graph.

e^0 = 1

e^-k (k>0) = 1/(e^k)

so your question is, is there a number M such that 1/M = 0? And hopefully you can answer this for yourself.

triprcMay 21 2009, 05:45:05 UTC 6 years ago

Knob job.

roadriverrailMay 21 2009, 17:55:10 UTC 6 years ago

triprcMay 21 2009, 20:06:47 UTC 6 years ago

roadriverrailMay 21 2009, 20:13:20 UTC 6 years ago

I'll also note that nobody here called you anything pejorative, that several people answered your question in multiple ways, and that the worst you ever got was people telling you you were off-topic.

So, I fail to see why your histrionics and calling someone a "knob job" was appropriate or even necessary.

triprcMay 21 2009, 20:40:14 UTC 6 years ago

roadriverrailMay 21 2009, 20:44:13 UTC 6 years ago

triprcMay 21 2009, 21:09:50 UTC 6 years ago

What can I say? I was raised in the city on the East Coast. Sticks and stones.

czarandyMay 21 2009, 02:23:06 UTC 6 years ago

For example: printf("%lf\n", exp(-1e20)) may print 0, depending on the compiler/platform.

roadriverrailMay 21 2009, 19:10:37 UTC 6 years ago

triprcwrote inalgorithms: ←(No Subject)notthebuddhawrote inalgorithms: →Big-O for other parameters?